std::vector::clear
Removes all elements from the vector (which are destroyed), leaving the container with a size of 0.
移除vector内所有元素(并销毁他们),使容器大小为变为0(size而不是capacity)。
例子:
#include <iostream> #include <vector> using namespace std; int main() { vector<int> vi={10,20,30}; cout<<"size="<<vi.size()<<endl; cout<<"capacity="<<vi.capacity()<<endl; vi.clear(); cout<<"size="<<vi.size()<<endl; cout<<"capacity="<<vi.capacity()<<endl; cout<<"vi[1]="<<vi[1]<<endl; }
运行结果:
发现数据还是没有被销毁阿。。。
A reallocation is not guaranteed to happen, and the vector capacity is not guaranteed to change
due to calling this function. A typical alternative that forces a reallocation is to use swap:
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不保证会发生重分配,也不保证该函数会改变capacity,另一个备选的发生重分配的是swap。
Parameters
none
Return value
none
Example
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Output:
myvector contains: 100 200 300
myvector contains: 1101 2202
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Complexity
Linear in size (destructions).
This may be optimized to constant complexity for trivially-destructible types (such as scalar
or PODs), where elements need not be destroyed.
复杂度和其大小线性相关(析构)
最优复杂度可能是常量时间复杂度,因为可能其中的元素不需要析构。
Iterator validity
All iterators, pointers and references related to this container are invalidated.
所有的迭代器,指针以及引用都将失效。
#include <iostream> #include <vector> using namespace std; int main() { vector<int> vi={10,20,30}; cout<<"size="<<vi.size()<<endl; cout<<"capacity="<<vi.capacity()<<endl; int &ri=vi[0]; auto it=vi.begin(); vi.clear(); cout<<"size="<<vi.size()<<endl; cout<<"capacity="<<vi.capacity()<<endl; cout<<"vi[1]="<<vi[1]<<endl; cout<<"ri="<<ri<<endl; cout<<"vi.begin()="<<*it<<endl; }
坑我的吧,怎么都没有失效??
Data races
The container is modified.
All contained elements are modified.
容器将被访问。
所有容器元素都将被修改。
Exception safety
No-throw guarantee: this member function never throws exceptions.
该成员方法不会抛出异常。
//翻译的不好的地方请多多指导,可以在下面留言或者点击左上方邮件地址给我发邮件,指出我的错误以及不足,以便我修改,更好的分享给大家,谢谢。
转载请注明出处:http://blog.csdn.net/qq844352155
2014-8-15
于GDUT