C++ primer plus第六版课后编程题答案6.5


//6.5
#include <iostream>
#include<cctype>
using namespace std;

void main65()
{
	int salary;
	cout<<"Enter your salary:";
	cin>>salary;
	while(salary>=0)//&&isdigit(salary))
	{
		if(salary<5000)
			cout<<"Your salary is "<<salary<<"  You shouldn't!"<<endl;
		else if(salary<15000)
			cout<<"Your salary is "<<salary<<" ,Your sui is "<<salary*0.1<<endl;
		else if(salary<35000)
			cout<<"Your salary is "<<salary<<" ,Your sui is "<<salary*0.15<<endl;
		else
			cout<<"Your salary is "<<salary<<" ,Your sui is "<<salary*0.2<<endl;

		cout<<"Enter your salary:";
		cin>>salary;
	}

	//cout<<salary<<"  isdigit()"<<endl;//<<isdigit(salary)<<endl;
	cout<<"Finish!";

	cin.get();
	system("pause");



}

 

 

//2014-8-13

发现有个bug

那就是isdigit()函数的原型为

int isdigit(char c)

参数应该是一个char字符,如果是int类型,无论传递什么参数,返回的都是一个false值,salary的类型应该是char.

修改后的程序为:

 

#include <iostream>  
#include<cctype>  
using namespace std;  
  
int main()  
{  
    char salary;  
    cout<<"Enter your salary:";  
    cin>>salary;  
    while(salary>=0&&isdigit(salary))  
    {  
        if(salary<5000)  
            cout<<"Your salary is "<<salary<<"  You shouldn't!"<<endl;  
        else if(salary<15000)  
            cout<<"Your salary is "<<salary<<" ,Your sui is "<<salary*0.1<<endl;  
        else if(salary<35000)  
            cout<<"Your salary is "<<salary<<" ,Your sui is "<<salary*0.15<<endl;  
        else  
            cout<<"Your salary is "<<salary<<" ,Your sui is "<<salary*0.2<<endl;  
  
        cout<<"Enter your salary:";  
        cin>>salary;  
    }  
  
    //cout<<salary<<"  isdigit()"<<endl;//<<isdigit(salary)<<endl;  
    cout<<"Finish!"<<endl;  
  
    cin.get();  

  
  
  
}

但是考虑到isdigit是检测单个字符,因此弃用。
修改完善后的程序如下:

 

#include <iostream>  
#include<cctype>  
using namespace std;  
  
int main()  
{  
    int salary;  
    cout<<"Enter your salary:";    
    while(cin>>salary&&salary>=0)  
    {  
        if(salary<5000)  
            cout<<"Your salary is "<<salary<<"  You shouldn't!"<<endl;  
        else if(salary<15000)  
            cout<<"Your salary is "<<salary<<" ,Your sui is "<<salary*0.1<<endl;  
        else if(salary<35000)  
            cout<<"Your salary is "<<salary<<" ,Your sui is "<<salary*0.15<<endl;  
        else  
            cout<<"Your salary is "<<salary<<" ,Your sui is "<<salary*0.2<<endl;  
  
        cout<<"Enter your salary:";  
       // cin>>salary;  
    }  
  
    //cout<<salary<<"  isdigit()"<<endl;//<<isdigit(salary)<<endl;  
    cout<<"error	!Finish!"<<endl;  
  
    cin.get();  

  
  
  
}

在linux下的运行截图:


感谢网友:ffx372580856zhy137879的提醒,谢谢。

—–2014-8-13
于GDUT

 

 

 

 

 

 


发表回复

您的电子邮箱地址不会被公开。 必填项已用 * 标注