std::thread::detach
void detach();
Detaches the thread represented by the object from the calling thread, allowing them to execute independently from each other.
将本线程从调用线程中分离出来,允许本线程独立执行。(但是当主进程结束的时候,即便是detach()出去的子线程不管有没有完成都会被强制杀死)
例子:
#include <iostream> #include <thread> #include <vector> #include <ctime> #include <fstream> using namespace std; //delay(n) 延时n秒 void delay(double sec) { time_t start_time, cur_time; // 变量声明 time(&start_time); do { time(&cur_time); }while((cur_time - start_time) < sec ); }; void show(int n){ ofstream fout("detach.txt"); if(!fout.is_open()) cout<<"open failed!"<<endl; while(n>0){ fout<<"1currentThread is "<<pthread_self()<<",Now n is "<<n<<endl; delay(0.2); n--; } fout<<"ok"<<endl; fout.close(); } int main() { cout<<"main starts"<<endl; thread t(show,100); t.detach(); delay(1); cout<<"main complete!"<<endl; }
运行截图:
可以看出,当进程结束的时候,即便detach没有完成任务也会被强制杀死。
Both threads continue without blocking nor synchronizing in any way. Note that when either one ends execution, its resources are released.
两个线程不会堵塞也不会同步,注意他们任一一个结束的时候,所持有的资源将会被释放。
After a call to this function, the thread object becomes non-joinable and
can be destroyed safely.
调用该方法后,该线程对象变得不可连接以及可以安全地销毁。
例子:
Parameters
none
Return value
none
Example
|
|
Output (after 5 seconds):
Spawning and detaching 3 threads...
Done spawning threads.
(the main thread will now pause for 5 seconds)
pause of 1 seconds ended
pause of 2 seconds ended
pause of 3 seconds ended
pause of 5 seconds ended
|
Data races
The object is modified.
Exception safety
Basic guarantee: if an exception is thrown by this member function, the thread object is
left in a valid state.
If the call fails, a system_error exception is thrown:
exception type | error condition | description |
---|---|---|
system_error | errc::invalid_argument | The thread object is not joinable |
system_error | errc::no_such_process | The thread object is not valid |
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//写的错误或者不好的地方请多多指导,可以在下面留言或者点击左上方邮件地址给我发邮件,指出我的错误以及不足,以便我修改,更好的分享给大家,谢谢。
转载请注明出处:http://blog.csdn.net/qq844352155
author:天下无双
Email:coderguang@gmail.com
2014-9-3
于GDUT
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