std::any_of
template <class InputIterator, class UnaryPredicate>
bool any_of (InputIterator first, InputIterator last, UnaryPredicate pred);
Returns true
if pred returns true
for any of the elements in the range [first,last)
, and false
otherwise.
如果范围内任一元素使pred返回true,则返回true,否则返回false.
例子:
#include <iostream> #include <algorithm> using namespace std; bool isGreat(int i){ if(i>=5){ cout<<i<<">=5"<<" ,match!"<<endl; return true; } else{ cout<<i<<"<5"<<" ,mismatch!"<<endl; return false; } } int main() { vector<int> vi{0,1,2,3,4,5,6}; if(any_of(vi.begin(),vi.end(),isGreat)) cout<<"Yes,some elements in vi >=5 "<<endl; else cout<<"no,all elements in vi didn't >=1 "<<endl; cout<<endl; int ar[5]={10,20,30,40,50}; if(any_of(ar,ar+5,[](int i){return i%10;})) cout<<"some in ar can %10!=0"<<endl; else cout<<"all %10=0!"<<endl; }
运行截图:
If [first,last)
is an empty range, the function returns false
.
如果范围为空,则返回false.(因为没有任一匹配)
例子:
#include <iostream> #include <algorithm> using namespace std; bool isGreat(int i){ if(i>=5){ cout<<i<<">=5"<<" ,match!"<<endl; return true; } else{ cout<<i<<"<5"<<" ,mismatch!"<<endl; return false; } } int main() { vector<int> vi{0,1,2,3,4,5,6}; if(any_of(vi.begin(),vi.begin(),isGreat)) cout<<"emptiy=true "<<endl; else cout<<"emptiy=false "<<endl; }
The behavior of this function template is equivalent to:
行为类似以下:
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Parameters
-
first, last
Input iterators to the initial
and final positions in a sequence. The range used is[first,last)
, which contains all theelements between first and last, including the element pointed by first but not the
element pointed by last. -
标示序列范围的输入迭代器。包含了first,last之间的所有元素,包括first指向的元素,但不包括last.
pred
- Unary function that accepts an element in the range as argument and returns a value convertible to
bool
. The value returned indicates whether the element fulfills the condition checked
by this function.
The function shall not modify its argument.
This can either be a function pointer or a function object.
-
一个接受一个元素类型参数并返回一个bool值的一元函数。
-
可以是一个指针或者函数对象。
-
Return value
true
if pred returns true
for any of the elements in the range [first,last)
, and false
otherwise.
如果任一的元素对pred的返回值是true,那么返回true,否则返回false.
If [first,last)
is an empty range, the function returns false
.
如果范围为空,则返回false.
Example
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|
Output:
There are negative elements in the range.
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Complexity
Up to linear in the distance between first and last: Calls pred for
each element until a match is found.
和first,last之间的距离线性相关,对每个元素调用pred直到一个匹配的值。
Data races
Some (or all) of the objects in the range [first,last)
are accessed (once at most).
最少一个元素被访问。
Exceptions
Throws if either pred or an operation on an iterator throws.
Note that invalid parameters cause undefined behavior.
如果pred或者操作迭代器会抛出异常就会抛出异常。
无效的参数导致未定义的行为。
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//写的错误或者不好的地方请多多指导,可以在下面留言或者点击左上方邮件地址给我发邮件,指出我的错误以及不足,以便我修改,更好的分享给大家,谢谢。
转载请注明出处:http://blog.csdn.net/qq844352155
author:天下无双
Email:coderguang@gmail.com
2014-9-1
于GDUT
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